Sorting from Counterexamples

arXiv:2608.21579v1 Announce Type: new Abstract: Consider the following problem of learning an unknown linear order on n items. In each round, the learner guesses a complete ordering of the items and receives either confirmation that the guess is correct or a counterexample: a pair of items in the wrong order. The goal is to identify the unknown order using as few queries as possible. We study this problem when up to k of the returned counterexamples may be untruthful, where k is not known in advance. We determine the optimal query complexity up to constant factors: [ Theta(nlog n + nk). ] Thus, while the noiseless complexity matches the classical complexity of sorting, each untruthful counterexample incurs an additional cost of order n. The upper bound is based on a geometric representation of permutations and Grunbaum's theorem, while the lower bound combines sorting arguments with a Condorcet-type construction. We also study the case where the target ranking has a low-dimensional geometric representation: each item is represented by a point in R^d, and the ranking is obtained by projecting the points onto an unknown direction. For these classes we give an upper bound of O(d^2log n+dk) and a lower bound of Omega(dlog n+dk), leaving a factor of d gap in the noiseless term.

Source: arXiv cs.LG | 2026-08-25